1. Some masons promised to do a work in 10 days but 8 of them were absent and remaining did the work in 18 days. What was the original number of masons?
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By: anil on 05 May 2019 02.04 am
Let original number of masons = $$x$$ Using, $$M_1D_1=M_2D_2$$ => $$x imes10=(x-8) imes18$$ => $$10x=18x-144$$ => $$18x-10x=144$$ => $$x=frac{144}{8}=18$$ $$ herefore$$ Original number of masons = 18 => Ans - (D)
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