1. In ΔPQR measure of angle Q is $$90^\circ$$. If $$cot P = \frac{8}{15}$$, and PQ = 4cm, then what is the length (in cm) of side PR?
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By: anil on 05 May 2019 03.00 pm
Given : PQ = 4 cm and $$cot P = frac{8}{15}$$ To find : PR = ? Solution : In right $$ riangle$$ PQR, => $$cot(P)=frac{PQ}{QR}$$ => $$frac{8}{15}=frac{4}{QR}$$ => $$QR=frac{15}{8} imes4=7.5$$ cm $$ herefore$$ $$(PR)^2=(PQ)^2+(QR)^2$$ => $$(PR)^2=(4)^2+(7.5)^2$$ => $$(PR)^2=16+56.25=72.25$$ => $$PR=sqrt{72.25}=8.5$$ cm => Ans - (A)
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