1. In ∆PQR measure of angle Q is $$90^\circ$$. If $$ cosec P = \frac{17}{15}$$, and PQ = 0.8cm, then what is the length (in cm) of side QR?
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By: anil on 05 May 2019 03.00 pm
Given : $$cosec P$$ = $$frac{17}{15}$$ Also, $$cosec P=frac{PR}{QR}=frac{17}{15}$$ Let PR = $$17x$$ cm and QR = $$15x$$ cm Thus, in $$ riangle$$ PQR, => $$(PQ)^2=(PR)^2-(QR)^2$$ => $$(PQ)^2=(17x)^2-(15x)^2$$ => $$(PQ)^2=289x^2-225x^2=64x^2$$ => $$PQ=sqrt{64x^2}=8x$$ cm According to ques, => $$8x=0.8$$ => $$x=frac{0.8}{8}=frac{1}{10}$$ $$ herefore$$ QR = $$15 imesfrac{1}{10}=1.5$$ cm => Ans - (D)
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