1. The average of three numbers is 40. First number is 4/3 of the third number. If third number is 20 less than second number, then what is the value of second number?
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By: anil on 05 May 2019 02.02 am
Let the third number = $$3x$$ => First number = $$frac{4}{3} imes3x=4x$$ Second number = $$3x+20$$ Sum of the three numbers = $$40 imes3=120$$ According to ques, => $$(3x)+(4x)+(3x+20)=120$$ => $$10x=120-20=100$$ => $$x=frac{100}{10}=10$$ $$ herefore$$ Second number = $$(3 imes10)+20=50$$ => Ans - (B)
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