1. What is the value of equation $$a^3 + b^3 + c^3 - 3abc$$ if $$a^2 + b^2 + c^2 = ab + bc + ca + 4$$ and $$a + b + c = 4$$
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By: anil on 05 May 2019 02.02 am
Given : $$a + b + c = 4$$ -----------(i) and $$a^2 + b^2 + c^2 = ab + bc + ca + 4$$ => $$a^2 + b^2 + c^2 - ab - bc - ca = 4$$ ------------(ii) To find : $$a^3 + b^3 + c^3 - 3abc$$ = $$(a+b+c)(a^2+b^2+c^2-ab-bc-ca)$$ Substituting values from equations (i) and (ii), we get : = $$4 imes4=16$$ => Ans - (C)
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