First 20 multiples of 9 = $$9,18,27,......,171,180$$ => Sum = $$9(1+2+3+.....+19+20)$$ = $$9 imesfrac{20(20+1)}{2}$$ $$[ecause$$ Sum of first $$n$$ integers $$=frac{n(n+1)}{2}]$$ = $$9 imes10 imes21=1890$$ => Average = $$frac{1890}{20}=94.5$$ => Ans - (D)
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