1. In a certain office, 1/3 of the workers are women, 1/2 of the women are married and 1/3 of the married women have children. If 3/4 of the men are married and 2/3 of the married men have children, then what part of workers are without children?
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By: anil on 05 May 2019 02.00 am
Let the total number of workers in the office be $$900x$$ => No. of women = $$frac{900x}{3} = 300x$$ No. of married woman = $$frac{300x}{2} = 150x$$ No. of married woman having children = $$frac{150x}{3} = 50x$$ => No. of women NOT having children = $$300x - 50x = 250x$$ No. of men = $$900x-300x = 600x$$ No. of married men = $$frac{3}{4} * 600x = 450x$$ No. of married men having children = $$frac{2}{3} * 450x = 300x$$ => No. of men NOT havin children = $$600x - 300x = 300x$$ Now, total no. of workers not having children = $$250x + 300x = 550x$$ $$ herefore$$ Fraction of people without children = $$frac{550x}{900x} = frac{11}{18}$$
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