1. The product of two numbers is 45 and their difference is 4. The sum of squares of the two numbers is
Write Comment
Comments
By: anil on 05 May 2019 02.00 am
As we know $$(a-b)^{2}$$ = $$a^{2} + b^{2} - 2ab$$
We assume that first number is a and second number is b hence ab = 45
and a - b = 4
after putiing values we will get $$a^{2} + b^{2}$$ = 106
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
We assume that first number is a and second number is b hence ab = 45
and a - b = 4
after putiing values we will get $$a^{2} + b^{2}$$ = 106