1. $$sin^{2}$$ $$\theta - 3 sin \theta + 2 = 0$$ will be true if
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By: anil on 05 May 2019 02.58 pm
Given that $$sin^{2}$$ θ - 3 sin θ + 2 = 0 $$sin^{2}$$ θ - 2 sin θ - sin θ + 2 = 0
sin θ (sin θ - 2) - 1 (sin θ - 2) = 0 (sin θ - 2)(sin θ - 1) = 0 here, sin θ = 2 is not a possible value as max value of sin θ = 1 and so sin θ = 1 and sin θ takes value 1 at θ = 90 degree
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sin θ (sin θ - 2) - 1 (sin θ - 2) = 0 (sin θ - 2)(sin θ - 1) = 0 here, sin θ = 2 is not a possible value as max value of sin θ = 1 and so sin θ = 1 and sin θ takes value 1 at θ = 90 degree