1. If sec x + cos x = 3, then $$tan^{2}x - sin^{2}x$$ is
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By: anil on 05 May 2019 01.50 am
Expression : $$sec x + cos x = 3$$ Squaring both sides, we get : => $$sec^2 x + cos^2 x + 2.sec x . cos x = 9$$ => $$sec^2 x + cos^2 x = 9-2 = 7$$ To find : $$tan^{2}x - sin^{2}x$$ = $$sec^2 x - 1 - (1 - cos^2 x)$$ = $$sec^2 x + cos^2 x - 2 = 7-2 = 5$$
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