Let the given sum = Rs. $$1000x$$ Rate of interest = 10% and time period = 3 years Compound interest = $$P [(1 + frac{R}{100})^T - 1]$$ = $$1000x [(1 + frac{10}{100})^3 - 1]$$ = $$1000x [(frac{11}{10})^3 - 1] = 1000x (frac{1331 - 1000}{1000})$$ = $$1000x imes frac{331}{1000} = 331x$$ Simple interest = $$frac{P imes R imes T}{100}$$ = $$frac{1000x imes 10 imes 3}{100} = 300x$$ => Difference between simple and compound interests = $$331-300x = 93$$ => $$31x = 93$$ => $$x = frac{93}{31} = 3$$ $$ herefore$$ Value of given sum = $$1000 imes 3 = Rs. 3,000$$