1. The greatest perfect square number of 6 digits is
Write Comment
Comments
By: anil on 05 May 2019 01.50 am
Let $$x^2$$ be the largest 6-digit perfect square. The largest six digit number is 999,999 and so $$x^2$$ < 999,999 We know that $$(1,000)^2=1,000,000$$ which is only 1 more than 999,999 and so $$x^2$$ must be the next smaller square which is $$(1000-1)^2$$ = $$(999)^2$$ = 998,001 => Ans - (B)
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use