1. The least number, which when divided by 5, 6, 7 and 8 leaves a remainder 3 in each case, but when divided by 9 leaves no remainder, is:
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By: anil on 05 May 2019 01.49 am
L.C.M. of 5, 6, 7 and 8 = 840 Thus, required number is of the form = $$840k+3$$ Least value of $$k$$ for which $$(840k+3)$$ is divisible by 9 is $$k=2$$ $$ herefore$$ Required number = $$840 imes 2+3=1683$$ => Ans - (B)
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