1. The product of two 2-digit numbers is 2160 and their H.C.F. is 12. The numbers are
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By: anil on 05 May 2019 01.48 am
Let the two numbers be $$12x$$ and $$12y$$ respectively where $$x$$ and $$y$$ are co-primes Product of numbers = $$(12x) imes (12y)=2160$$ => $$xy=frac{2160}{144}=15$$ Possible pairs of $$x$$ and $$y$$ whose H.C.F. is 1 = $$(3,5)$$ $$ herefore$$ Required numbers = $$(12 imes 3),(12 imes 5)$$ = 36 , 60 => Ans - (C)
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