1. If $$( x - 5)^{2}$$ + $$(y - 2)^{2}$$ + $$(z - 9)^{2}$$ = 0 , then value of (x + y - z) is
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By: anil on 05 May 2019 01.48 am
Expression : $$( x - 5)^{2}$$ + $$(y - 2)^{2}$$ + $$(z - 9)^{2}$$ = 0 $$ecause$$ If sum of three positive numbers is zero, then the numbers are equal to zero => $$(x-5)^2=0$$ => $$(x-5)=0$$ => $$x=5$$ Similarly, $$y=2$$ and $$z=9$$
To find : $$(x+y-z)$$ = $$5+2-9=-2$$ => Ans - (C)
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To find : $$(x+y-z)$$ = $$5+2-9=-2$$ => Ans - (C)