1. If a+b+c=27, then what is the value of $$(a-7)^{3}+(b - 9)^{3}+(c - 11)^{3}-3(a - 7)(b - 9)(c - 11)$$ ?
Write Comment
Comments
By: anil on 05 May 2019 01.48 am
If x+y+z = 0, $$(x)^{3}+(y)^{3}+(z)^{3}-3(x)(y)(z)=0$$ puty x = a-7, y = b-9, z = c-11, then x+y+z = (a+b+c)-(7+11+9) = 27 - 27 = 0, so $$(x)^{3}+(y)^{3}+(z)^{3}-3(x)(y)(z)=0$$ $$(a-7)^{3}+(b - 9)^{3}+(c - 11)^{3}-3(a - 7)(b - 9)(c - 11)=0$$ so the answer is option A.
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use