1. What least value which should be added to 1812 to make it divisible by 7, 11 and 14?
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By: anil on 05 May 2019 01.48 am
L.C.M.(7,11,14) = 154 Now, on dividing 1812 by 154, => $$1812=154 imes11+118$$ Thus, the least value which should be added to 1812 to make it divisible by 7, 11 and 14 = $$154-118=36$$ => Ans - (B)
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