1. If (x - y) = 7, then what is the value of $$(x-15)^{3}-(y-8)^{3}$$ ?
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By: anil on 05 May 2019 01.48 am
To find : $$(x-15)^{3}-(y-8)^{3}$$ Let $$(x-15)=a$$ and $$(y-8)=b$$ Thus, we need to find : $$a^3-b^3$$ -----------(i) => $$x=a+15$$ and $$y=b+8$$ ---------(ii) It is given that, $$(x-y)=7$$ Substituting values from equation (ii), => $$(a+15)-(b+8)=7$$ => $$a-b+7=7$$ => $$a-b=0$$ Cubing both sides, we get : => $$a^3-b^3-3ab(a-b)=0$$ => $$a^3-b^3-3ab(0)=0$$ => $$a^3-b^3=0$$ => Ans - (A)
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