1. 30 men can do a piece of work in 16 days. How many men would be required to do the same work in 20 days ?
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By: anil on 05 May 2019 01.42 am
Using : $$M_1 D_1 = M_2 D_2$$ 30 men can do a piece of work in 16 days
=> $$M_1 = 30 , D_1 = 16$$ and $$D_2 = 20$$ Let $$M_2$$ men finish the same work in 20 days => $$30 imes 16 = M_2 imes 20$$ => $$M_2 = frac{480}{20} = 24$$
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=> $$M_1 = 30 , D_1 = 16$$ and $$D_2 = 20$$ Let $$M_2$$ men finish the same work in 20 days => $$30 imes 16 = M_2 imes 20$$ => $$M_2 = frac{480}{20} = 24$$