1. For the two given equations I and II. Give answer a: if p is greater than q. Give answer b: if p is smaller than q. Give answer c: if p is equal to q. Give answer d: if p is either equal to or greater than q. Give answer e: if p is either equal to or smaller than q.I. $$p^2 + 5p + 6 = 0$$ II. $$q^2 + 3q + 2 = 0$$






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  • By: anil on 05 May 2019 01.40 am
    I : $$p^2 + 5p + 6 = 0$$ => $$p^2 + 3p + 2p + 6 = 0$$ => $$p (p + 3) + 2 (p + 3) = 0$$ => $$(p + 2) (p + 3) = 0$$ => $$p = -2 , -3$$ II : $$q^2 + 3q + 2 = 0$$ => $$q^2 + q + 2q + 2 = 0$$ => $$q (q + 1) + 2 (q + 1) = 0$$ => $$(q + 2) (q + 1) = 0$$ => $$q = -2 , -1$$ $$ herefore p leq q$$
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