1.
In each of the questions a pair of equations is given. You have to find out the values of x and y and give answer.I. $$4x^2 = 49$$ II. $$9y^2 - 66y + 121 = 0$$
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By: anil on 05 May 2019 01.33 am
$$4x^2 = 49$$
$$x = frac{7}{2}, -frac{7}{2}$$ $$9y^2-66y+121 = 0$$
$${(3y-11)}^2 = 0$$
$$y = frac{11}{3}$$ x < y
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$$x = frac{7}{2}, -frac{7}{2}$$ $$9y^2-66y+121 = 0$$
$${(3y-11)}^2 = 0$$
$$y = frac{11}{3}$$ x < y