1. $$76\% of (?) - (11)^2 = 525$$






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  • By: anil on 05 May 2019 03.14 am
    The question is supposed to be $$76\% of (?) - (11)^{2} = 525$$
    Let the unknown term be $$x$$.
    $$76$$% of $$x$$ = $$525+11^{2}$$=$$646$$
    $$x$$=$$frac{646 imes100}{76}$$=$$850$$
  • By: anil on 05 May 2019 03.14 am
    The question is supposed to be $$76\% of (?) - (11)^{2} = 525$$
    Let the unknown term be $$x$$.
    $$76$$% of $$x$$ = $$525+11^{2}$$=$$646$$
    $$x$$=$$frac{646 imes100}{76}$$=$$850$$
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