1. Which of the following combinations is wrong?





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MCQ-> Analyse the following passage and provide appropriate answers for the questions that follow: Each piece, or part, of the whole of nature is always merely an approximation to the complete truth, or the complete truth so far as we know it. In fact, everything we know is only some kind of approximation, because we know that we do not know all the laws as yet. Therefore, things must be learned only to be unlearned again or, more likely, to be corrected. The principal of science, the definition, almost, is the following: The test of all knowledge is experiment. Experiment is the sole judge of scientific “truth.” But what is the source of knowledge? Where do the laws that are to be tested come from? Experiment, itself, helps to produce these laws, in the sense that it gives us hints. But also needed is imagination to create from these laws, in the sense that it gives us hints. But also needed is imagination to create from these hints the great generalizations – to guess at the wonderful, simple, but very strange patterns beneath them all, and then to experiment to check again whether we have made the right guess. This imagining process is so difficult that there is a division of labour in physics: there are theoretical physicists who imagine, deduce, and guess at new laws, but do not experiment; and then there are experimental physicists who experiment, imagine, deduce, and guess. We said that the laws of nature are approximate: that we first find the “wrong” ones, and then we find the “right” ones. Now, how can an experiment be “wrong”? First, in a trivial way: the apparatus can be faulty and you did not notice. But these things are easily fixed and checked back and forth. So without snatching at such minor things, how can the results of an experiment be wrong? Only by being inaccurate. For example, the mass of an object never seems to change; a spinning top has the same weight as a still one. So a “law” was invented: mass is constant, independent of speed. That “law” is now found to be incorrect. Mass is found is to increase with velocity, but appreciable increase requires velocities near that of light. A true law is: if an object moves with a speed of less than one hundred miles a second the mass is constant to within one part in a million. In some such approximate form this is a correct law. So in practice one might think that the new law makes no significant difference. Well, yes and no. For ordinary speeds we can certainly forget it and use the simple constant mass law as a good approximation. But for high speeds we are wrong, and the higher the speed, the wrong we are. Finally, and most interesting, philosophically we are completely wrong with the approximate law. Our entire picture of the world has to be altered even though the mass changes only by a little bit. This is a very peculiar thing about the philosophy, or the ideas, behind the laws. Even a very small effect sometimes requires profound changes to our ideas.Which of the following options is DEFINITLY NOT an approximation to the complete truth?
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MCQ-> In each question below, a group of digits/symbols is given, followed by four combinations of letters numbered (1), (2), (3), and (4). You have to find out which of the combinations (1), (2), (3) and (4) correctly represents the group of digits/symbols based on the following coding system and the conditions those follow and mark the number of that combination as your answer. If none of the four combinations correctly represents the group of digits/symbols, mark (5) i.e.,’None of these’ as the answer Digit/Symbol 5 9 @ © 3 8 1 $ % 4 2 6 * 7 $$\delta$$ # Letter Code B E P A K D F H Q I R J U M V T Conditions (a) If the first unit in the group is an even digit and the last unit is a symbol, both these are to be coded as the code for the symbol. (b) If the first unit in the group is an odd digit and the last unit is an even digit, their codes are to the unchanged. (c) If both the first and the last units in the group are symbols, both these are to be coded as ‘X’.@91$26
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MCQ-> In each question below is given a group of letters followed by four combinations of digits/symbols numbered a:, b:, c: and d:. You have to find out which of the combinations correctly represents the group of letters based on the following coding system and the conditions that follow arid mark the number of that combination as your answer. If none of the combinations correctly repreients the group of letters, marks e: i.e. ‘None of these’ as your answer. Conditions(i) If1the first letter is a vowel and the last letter is a consonant both are to be coded as *. (ii) If the first letter Is a consonant and the last letter is a vowel their codes are to be interchanged. (iii) If both the first and the last letters are vowels both are to be coded as the first letter.IFNVDE
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MCQ-> In each question below is given a group of letters followed by four combinations of digits/symbols numbered a:, b:. c: and d:. You have to find out which of the combinations correctly represents the group of letters based on the following coding system and the conditions and mark the number of that combination as your answer. If none of the four combinations correctly represents the group of letters, give e: i.e. ‘None of these’ as the answer.Conditions : (i) If the first letter is a consonant and the last letter is a vowel, their codes are to be interchanged. (ii) If both the first and the last letters are vowels, both are to be coded as *. (iii) If the first letter is a vowel and the last letter is a consonant, both are to be coded as the code for the consonant.TUKDIP
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MCQ-> In each question below is given a group of letters followed by four combinations of digits/symbols numbered a), b), c), and d).You have to find out which of the combinations correctly represents the group of letters based on the following coding system and the conditions that follow and mark the number of that combination as your answer.If none of the combinations correctly represents the group of letters mark e)i.e None of these as your answer. Conditions: (i) If the first letter is a consonant and the last letter is a vowel their codes are to be interchanged. (i)If both the first and the last letters are vowels both are to be coded as the code for the first letter. (iii)If both the first and the last letters are consonants both are to be coded as $$\delta$$.IDZQGY
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