68551. When the ac input signal is very large the instantaneous operating point CE amplifier moves all the way between
68552. For full wave rectification four diode bridge rectifier is claimed to have following advantages: Less expensive transformerSmall size transformerSuitable for higher voltage applications Which of these are correct?
68553. Following figure is a signal conditioning Amplifier, changes gain depending upon the polarity of Vs. What will be circuit voltage gain for + Vs and for - Vs if D2 is ideal.
68554. Which class of amplifiers operates with least distortion?
68555. In a full wave diode rectifier circuit each diode carries current for
68556. When a JFET is cut off, it's like an __________ switch and when it is saturated, it's like a __________ switch.
68557. The mobility of e- for Ge and Si respectively is
68558. If a capacitor C is charged by a constant current I, then the rate of change of voltage with time given by sweep speed equal to
68559. In operational Amplifier, Common mode voltage gain should be
68560. Which op-amp circuit uses a resistance in series with input and capacitor in feedback path?
68561. Saturation of iron core causes distortion.
68562. Which of the following is non-sinusoidal oscillator?
68563. Low gain-bandwidth product of a JFET is due to
68564. The circuit of the figure is an example of feedback of the following type
68565. Oscillation frequency in Wein bridge oscillator is
68566. Assertion (A): A class C amplifier can also be used as frequency multiplierReason (R): When narrow current pulses drive a resonant circuit the output can be a near perfect sine wave
68567. The parameter β of a BJT change by 300%. If self bias is used in the amplifier using this BJT, the quiescent value of IC and VCE remain almost the same.
68568. A bypass capacitor produces
68569. Rise time in a transistor is change from
68570. The common gate amplifier has a characteristically __________ input resistance and a __________ output resistance.
68571. For input and later stages, BI-FET op-amp use
68572. The emitter coupled pair of BJT's gives a linear transfer relation between the differential output voltage and the differential input voltage Vid only when the magnitude of Vid is less a times the thermal voltage, where a is
68573. In most transistor the collector region is made physically larger than the emitter region
68574. The leakage current in CB configuration may be around
68575. In figure VCC = + 30 V, IC corresponding to Q point is 1 mA. If RC = 5 kΩ and RE = 5 kΩ, VCE corresponding to Q point is
68576. I met J.K.Rowling--------------they say is the richest person in the worl(Relative clause)
68577. In which of the following circuits is op-amp used in open loop configuration?
68578. The student leader explained why he had to leave the panel discussion forum(Adverbial of’anger’)
68579. In a diode rectifier with a capacitance input filter, a surge current is likely to flow when the circuit is switched on. The cause of this surge current is
68580. In a CE amplifier it is desired that the signal should be able to swing equally in both directions. Then the Q point should be
68581. In a base driver amplifier the voltage gain is the ratio of
68582. Assertion (A): A class C amplifier is a timed amplifier which needs a tank circuit as the load in the collector circuit of the transistor for its proper operationReason (R): In class C operation collector current flows for less than 180° of the ac cycle and thus flows in pulses
68583. A junction Field Effect Transistor can operate in
68584. The re model equivalent circuit shown in figure is for
68585. CMRR is the ratio of differential voltage gain to common mode gain.
68586. The purpose of impedance matching in an amplifier circuit is to achieve
68587. For the circuit of figure the input and output Miller resistances are
68588. In a BJT CE amplifier circuit the value of coupling capacitor should be such that
68589. In order to rectify sinusoidal signals of millivolt range (< 0.6 V)
68590. CMRR of an op-amp is about 0.1.
68591. A transistor amplifier has poles ats1 = - 0.000245 x 109 rad/sec.s2 = - 0.0748 x 109 rad/sec.s3 = - 0.670 x 109 rad/sec.s4 = - 4.38 x 109 rad/sec.The upper 3 dB frequency of the amplifier will be
68592. In the circuit of figure for sinusoidal input the waveform of the output will be as shown in
68593. An engineer designs an amplifier to have a voltage gain of 60, but when constructed it only had a gain of 50. What value of feedback will double the gain?
68594. The maximum theoretical efficiency for class A amplifier is
68595. In the case of an amplifier, the normalised voltage gain is given by.where f0 is zero frequency, fP is pole frequency. For a standard frequency response of the amplifier,
68596. In a rectifier only a portion of input power is converted into DC power. The rest is AC power.
68597. The slope of the transfer characteristics of an N-channel JFET is
68598. She-------------tomorrow to attend the wedding (Modal verb)
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