A NOR gate is a universal gate. ?->(Show Answer!)

1. A NOR gate is a universal gate.

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MCQ-> Analyse the following passage and provide appropriate answers for the follow. Popper claimed, scientific beliefs are universal in character, and have to be so if they are to serve us in explanation and prediction. For the universality of a scientific belief implies that, no matter how many instances we have found positive, there will always be an indefinite number of unexamined instances which may or may not also be positive. We have no good reason for supposing that any of these unexamined instances will be positive, or will be negative, so we must refrain from drawing any conclusions. On the other hand, a single negative instance is sufficient to prove that the belief is false, for such an instance is logically incompatible with the universal truth of the belief. Provided, therefore, that the instance is accepted as negative we must conclude that the scientific belief is false. In short, we can sometimes deduce that a universal scientific belief is false but we can never induce that a universal scientific belief is true. It is sometimes argued that this 'asymmetry' between verification and falsification is not nearly as pronounced as Popper declared it to be. Thus, there is no inconsistency in holding that a universal scientific belief is false despite any number of positive instances; and there is no inconsistency either in holding that a universal scientific belief is true despite the evidence of a negative instance. For the belief that an instance is negative is itself a scientific belief and may be falsified by experimental evidence which we accept and which is inconsistent with it. When, for example, we draw a right-angled triangle on the surface of a sphere using parts of three great circles for its sides, and discover that for this triangle Pythagoras' Theorem does not hold, we may decide that this apparently negative instance is not really negative because it is not a genuine instance at all. Triangles drawn on the surfaces of spheres are not the sort of triangles which fall within the scope of Pythagoras' Theorem. Falsification, that is to say, is no more capable of yielding conclusive rejections of scientific belief than verification is of yielding conclusive acceptances of scientific beliefs. The asymmetry between falsification and verification, therefore, has less logical significance than Popper supposed. We should, though, resist this reasoning. Falsifications may not be conclusive, for the acceptances on which rejections are based are always provisional acceptances. But, nevertheless, it remains the case that, in falsification, if we accept falsifying claims then, to remain consistent, we must reject falsified claims. On the other hand, although verifications are also not conclusive, our acceptance or rejection of verifying instances has no implications concerning the acceptance or rejection of verified claims. Falsifying claims sometimes give us a good reason for rejecting a scientific belief, namely when the claims are accepted. But verifying claims, even when accepted, give us no good and appropriate reason for accepting any scientific belief, because any such reason would have to be inductive to be appropriate and there are no good inductive reasons.According to Popper, the statement "Scientific beliefs are universal in character" implies that....

MCQ-> Study the following information carefully and answer the given questions: A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule in each step. The following is an illustration of input and rearrangement. (All the numbers are two digits numbers.)Input : gate 20 86 just not 71 for 67 38 bake sun 55 Step I : bake gate 20 just not 71 for 67 38 sun 55 86 Step II : for bake gate 20 just not 67 38 sun 55 86 71 Step III : gate for bake 20 just not 38 sun 55 86 71 67 Step IV : just gate for bake 20 not 38 sun 86 71 67 55 Step V : not just gate for bake 20 sun 86 71 67 55 38 Step VI : sun not just gate for bake 86 71 67 55 38 20 and Step VI is the last step of the above input as the desired arrangement is reached. As per the rules followed in the above steps, and out in each of the following questions the appropriate step for the given input. Input : 31 rise gem 15 92 47 aim big 25 does 56 not 85 63 with moonHow many steps will be required to complete the rearrangement ?
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MCQ->Assertion (A): The output of a NOR gate is equal to the complement of OR of input variables. Reason (R): A XOR gate is a universal gate.

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MCQ-> In the following questions, the symbols @, ©. $, % and * are used with the following meaning as illustrated below ‘P ©Q’ means ‘P is not greater than Q.. ‘P % Q’ means ‘P is not smaller than Q’. ‘P * Q’ means ‘P is neither smaller than nor equal to Q’. ‘P @ Q’ means P is neither greater than nor equal to Q’. ‘P $ Q’ means ‘P is neither greater than nor smaller than Q’. Now in each of the following questions assuming the given statements to be true, find which of the two conclusions I and II given below them is/ are definitely true ? a: if only Conclusion 1 is true. b: if only Conclusion II is true. c: if either Conclusion I or II is true. d: if neither Conclusion I nor II is true. e: if both Conclusions I and li are true.Statements : K @ V. V © N, N % F Conclusions: I. F @ V II. K @ N....

MCQ-> In the following question the symbols @, © , * , $ and % are used with the following meaning as illustrated below:‘P * Q’ means ‘P is neither smaller than nor equal to Q’. ‘P © Q’ means ‘P is neither greater than nor equal to Q’. ‘P @ Q’ means ‘P is not greater than Q’. ‘P % Q’ means ‘ P is not smaller than Q’. ‘P $ Q’ means ‘P is neither smaller than nor greater than Q’. Now in each of the following questions assuming the given statement to be true find which of the two conclusions I and II given below them is/are definitely true ? Give answer a:if only Conclusion I is true. b:if only Conclusion II is true. c:if either Conclusion I or II is true. d:if neither Conclusion I nor II is true. e:if both Conclusions I and II are true.Statements:H@K, K % D, D $ B Conclusions: I.H @ B II.B @ K....