1. p and q are positive numbers such that $$p^q = q^p$$, and $$q = 9p$$. The value of p is
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By: anil on 05 May 2019 02.37 am
$$p^q = q^p$$.
It has been given that $$q = 9p$$.
Substituting, we get,
$$p^{9p}=(9p)^p$$
$$(p^p)^9 = 9^p*p^p$$
=> $$(p^p)^8 = 9^p$$
$$p^{8p}=9^p$$
Raising the power to $$frac{1}{p}$$ on both sides, we get,
$$p^8=9$$
$$p=sqrt[8]{9}$$.
Therefore, option D is the right answer.
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It has been given that $$q = 9p$$.
Substituting, we get,
$$p^{9p}=(9p)^p$$
$$(p^p)^9 = 9^p*p^p$$
=> $$(p^p)^8 = 9^p$$
$$p^{8p}=9^p$$
Raising the power to $$frac{1}{p}$$ on both sides, we get,
$$p^8=9$$
$$p=sqrt[8]{9}$$.
Therefore, option D is the right answer.