1. If the angles of a triangle are (2x - 8)$$^{o}$$, (2x + 18)$$^{o}$$and 6x$$^{o}$$. What is the value of 3x (in degrees)?
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By: anil on 05 May 2019 02.27 am
Sum of angles of a triangle = $$180^circ$$ => $$(2x-8)^circ+(2x+18)^circ+(6x)^circ=180^circ$$ => $$10x+10=180$$ => $$10x=180-10=170$$
=> $$x=frac{170}{10}=17$$ $$ herefore$$ $$3x=3 imes17=51$$ => Ans - (C)
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=> $$x=frac{170}{10}=17$$ $$ herefore$$ $$3x=3 imes17=51$$ => Ans - (C)