1. Of the 3 numbers whose average is 64, the first number is 1/3 times the sum of other 2. The first number is
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By: anil on 05 May 2019 02.09 am
Let the three numbers be $$x,y,z$$ Sum of three numbers = $$x + y + z = 64 imes 3 = 192$$ According to ques, => $$x = frac{1}{3} imes (y + z)$$ => $$x = frac{1}{3} imes (192 - x)$$ => $$3x = 192 - x$$ => $$3x + x = 4x = 192$$ => $$x = frac{192}{4} = 48$$ => Ans - (D)
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