1. A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
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By: anil on 05 May 2019 02.12 am
Work done by A in 20 days = $$frac{80}{100} = frac{4}{5}$$ Work done by A in 1 day = $$frac{frac{4}{5}}{20} = frac{4}{100} = frac{1}{25}$$ Work done by A and B in 3 days = $$frac{20}{100} = frac{1}{5}$$ (Because remaining 20% is done in 3 days by A and B) Work done by A and B in 1 day = $$frac{1}{15}$$ Work done by B in 1 day = $$frac{1}{15} - frac{1}{25} = frac{2}{75}$$ => B can complete the work in $$frac{75}{2}$$ days = 37.5 days
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