1. The average of 1^2 , 2^2 , 3^2 , 4^2 , 5^2 , 6^2 , 7^2 , 8^2 , 9^2 , 10^2 is :
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By: anil on 05 May 2019 01.59 am
sum of squares of first n natural numbers are $$frac{(n)(n+1)(2n+1)}{6}$$ average = $$frac{SumofElements}{NmberofElements}$$ we are given numbers as 1^2 , 2^2 , 3^2 , 4^2 , 5^2 , 6^2 , 7^2 , 8^2 , 9^2 , 10^2 Sum of 10 elements = $$frac{10 imes 11 imes 21}{6}$$ = 385 average = $$frac{385}{10}$$ = 38.5
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