1. If (5x^2 - 3y^2): xy = 11:2, and x,y are positive, then the value of x/y is:
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By: anil on 05 May 2019 01.59 am
it is given that (5x^2 - 3y^2): xy = 11:2 let divide the numerator and denominator of left hand side of the given equation by y^2 we will get , $$frac{5( frac{x}{y})^2 - 3}{frac{x}{y}}$$ = $$frac{11}{2}$$ let $$frac{x}{y}$$ = k So, $$frac{5k^2-3}{k}$$ = $$frac{11}{2}$$ Solving this we get , k = $$frac{3}{2}$$ hence $$frac{x}{y}$$ = $$frac{3}{2}$$
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