1. If x is a rational number and $$\frac{(x+1)^3-(x-1)^3}{(x+1)^2-(x-1)^2}=2$$ then the sum of numerator and denominator of x is





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  • By: anil on 05 May 2019 02.57 pm
    Given , $$frac{(x+1)^3-(x-1)^3}{(x+1)^2-(x-1)^2}=2$$
    On simplifying , we get $$frac{6x^2 +2}{4x}=2$$
    $$frac{3x^2 +1}{2x}=2$$
    $$3x^2 +1=4x$$
    $$3x^2-4x+1=0$$
    (3x-1)(x-1)=0
    As it was mentioned that x is rational number . Hence, x= $$frac{1}{3}$$
    Hence , 1+3 = 4.


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