1. ‘O’ is the centre of the circle, AB is a chord of the circle, OM┴ AB. If AB = 20 cm, OM = 2√11 cm, then radius of the circle is





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  • By: anil on 05 May 2019 01.52 am
    OM is perpendicular bisector of AB = 20 cm => BM = 10 cm and OM = 2$$sqrt{11}$$ In $$ riangle$$OBM radius, OB = $$sqrt{(OM)^2 + (BM)^2}$$ => OB = $$sqrt{100 + 44} = sqrt{144}$$ => OB = 12 cm
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