1. If $$\frac{m-a^2}{b^2+c^2}+\frac{m-b^2}{c^2+a^2}+\frac{m-c^2}{a^2+b^2}=3$$ then the value of m is
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By: anil on 05 May 2019 02.56 pm
SInce solving this problem algebraically is a very tedious process, let us put some values for a,b, and c. Then, we will try to match the options. Let a =1, b = 2 and c=3. $$frac{m-1}{13}+frac{m-4}{10}+frac{m-9}{5}=3$$ Taking LCM, we get, $$frac{10m-10+13m-52+26m-234}{130}=3$$ $$49m = 390 + 296$$ $$49m = 686$$ $$m = 14$$ Substituting a,b and c in options, only option C gives 14 as the answer. Hence, option C is the right answer.
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