1. If $$\frac{a}{b}+\frac{b}{a}=1$$, then the value of $$a^3+b^3$$ is
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By: anil on 05 May 2019 02.56 pm
Given : $$frac{a}{b}+frac{b}{a}=1$$ => $$frac{a^2+b^2}{ab}=1$$ => $$a^2+b^2=ab$$ -----------(i) We know that, $$(a^3+b^3)=(a+b)(a^2+b^2-ab)$$ Substituting value from equation (i), we get : => $$(a^3+b^3)=(a+b)(ab-ab)$$ => $$(a^3+b^3)=(a+b) imes 0=0$$ => Ans - (B)
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