1. The numbers x, y, z are respectively proportional to 2, 3, 5 and the sum of x, y and z is 80. If the number z is given by the equation z = ax-8,
then a is
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By: anil on 05 May 2019 01.48 am
Let $$x=2k$$ , $$y=3k$$ and $$z=5k$$ Sum = $$(x+y+z)=80$$ => $$2k+3k+5k=80$$ => $$10k=80$$ => $$k=frac{80}{10}=8$$ Thus, $$x=2 imes 8=16$$ and $$z=40$$ Also, $$z=ax-8$$ => $$40=16(a)-8$$ => $$16a=40+8=48$$ => $$a=frac{48}{16}=3$$ => Ans - (C)
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