1.
In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.I. $$2x^{2}+15x+27=0$$
II. $$2y^{2}+7y+6=0$$
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$$(2x+9)(x+3) = 0$$
$$x = -frac{9}{2}, -3$$ $$2y^2+7y+6 = 0$$
$$(2y+3)(y+2) = 0$$
$$y = -frac{3}{2}, -2$$ $$x < y$$