1. Three men or eight boys can du a piece of work in 17 days. How many days will two men and six boys together take to finish the same work ?
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By: anil on 05 May 2019 01.20 am
Given that , 3 men(M) or 8 boys(B) can do the work in 17 days i.e the capacity of 3 men and 8 boys is same.
Hence, 3M = 8B , which gives , M = $$frac{8}{3}$$*B We need to find , the time taken by 2M + 6B . Replacing M with $$frac{8}{3}$$*B we get 2*$$frac{8}{3}$$*B + 6B = $$frac{34}{3}$$*B.
But as 8 boys can do the job in 17days , $$frac{34}{3}$$ boys can do the same job in (18*7)$$frac{34}{3}$$ = 12 days.
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Hence, 3M = 8B , which gives , M = $$frac{8}{3}$$*B We need to find , the time taken by 2M + 6B . Replacing M with $$frac{8}{3}$$*B we get 2*$$frac{8}{3}$$*B + 6B = $$frac{34}{3}$$*B.
But as 8 boys can do the job in 17days , $$frac{34}{3}$$ boys can do the same job in (18*7)$$frac{34}{3}$$ = 12 days.