1. The population of a town is 9000. It the number of females increases by 5% and the males by 7.5%, what will be the total population after increase. The number of females currently is 3000.
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By: anil on 05 May 2019 02.28 am
Number of females = 3000 and number of males = 6000 Females increases by 5% and the males by 7.5% => Total population after increase = $$[3000+(frac{5}{100} imes3000)]+[6000+(frac{7.5}{100} imes6000)]$$ = $$(3000+150)+(6000+450)$$ = $$9600$$ => Ans - (A)
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