1. What is the name of the fitness spa chain started by Virat Kohli?
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By: anil on 05 May 2019 03.32 am
Let $$log_{5}{2}$$ = y $$Rightarrow$$ y = $$log_{10}{2}*log_{5}{10}$$ $$Rightarrow$$ y = $$log_{10}{2}(log_{5}{5}+log_{5}{2})$$
$$Rightarrow$$ y = $$log_{10}{2}(1+y)$$
$$Rightarrow$$ y = $$dfrac{log_{10}{2}}{1 - log_{10}{2}}$$
We know that $$log_{10}{2}$$ = 0.30103 is an irrational number. Also $${1 - log_{10}{2}}$$ is not a multiple of $$log_{10}{2}$$. Hence, we can say that y is an irrational number.
By: anil on 05 May 2019 03.32 am
Let $$log_{5}{2}$$ = y $$Rightarrow$$ y = $$log_{10}{2}*log_{5}{10}$$ $$Rightarrow$$ y = $$log_{10}{2}(log_{5}{5}+log_{5}{2})$$
$$Rightarrow$$ y = $$log_{10}{2}(1+y)$$
$$Rightarrow$$ y = $$dfrac{log_{10}{2}}{1 - log_{10}{2}}$$
We know that $$log_{10}{2}$$ = 0.30103 is an irrational number. Also $${1 - log_{10}{2}}$$ is not a multiple of $$log_{10}{2}$$. Hence, we can say that y is an irrational number.
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$$Rightarrow$$ y = $$log_{10}{2}(1+y)$$
$$Rightarrow$$ y = $$dfrac{log_{10}{2}}{1 - log_{10}{2}}$$
We know that $$log_{10}{2}$$ = 0.30103 is an irrational number. Also $${1 - log_{10}{2}}$$ is not a multiple of $$log_{10}{2}$$. Hence, we can say that y is an irrational number.