1. A dealer sells two machines at Rs 12000 each. On one it gains 32% and on the other it looses 32%. What is its profit/loss percentage in the whole transaction?
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By: anil on 05 May 2019 01.47 am
Selling price of each item = Rs. 12000 Profit % on 1st item = 32% => Cost price of 1st item = $$12000 imesfrac{100}{(100+32)}=Rs.$$ $$9090.90$$ Similarly cost price of 2nd item = $$12000 imesfrac{100}{(100-32)}=Rs.$$ $$17647.06$$ => Total cost price = Rs. (9090.90+17647.06) = Rs. 26737.96 and total selling price = Rs. (12000+12000) = Rs. 24000 $$ herefore$$ Loss % = $$frac{26737.96-24000}{26737.96} imes100$$ = $$10.24\%$$ => Ans - (D)
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