1. An urn contains 6 red, 4 blue, 2 green and 3 yellow marbles.If three marbles are picked at random, what is the probability that two are blue and one is yellow?
 






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  • By: anil on 05 May 2019 01.31 am
    Number of ways of selecting 2 blue urns and 1 yellow urn = $$^{4}C_2* ^{3}C_1$$ = 18 Probability of selecting 2 blue urns and 1 yellow urn  = $$frac{18}{^{15}C_3}$$ = $$frac{18}{455}$$
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