1. Four identical coins are placed in a square. For each coin the ratio of area to circumference is same as the ratio of circumference to area. Then find the area of the square that is not covered by the coins.
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By: anil on 05 May 2019 02.31 am
$$frac{(pi r^2)}{2 pi r}$$ = $$frac{2 pi r}{ pi r^2}$$
So r = 2
Hence required area = (Area of square) - (Area of 4 circles)
= $$(8^2) - (4 pi (2^2))$$ (As side of square will be 4*2 = 8)
= $$16 (4- pi)$$
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So r = 2
Hence required area = (Area of square) - (Area of 4 circles)
= $$(8^2) - (4 pi (2^2))$$ (As side of square will be 4*2 = 8)
= $$16 (4- pi)$$