1. In an isosceles triangle DEF, ∠D = 130°. If I is the incentre of the triangle, then what is the value (in degrees) of ∠EIF?
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- By: anil on 05 May 2019 02.26 amGiven : I is the incentre of $$ riangle$$ DEF and $$angle$$ D = 130° To find : $$angle$$ EIF = $$ heta$$ = ? Incentre of a triangle = $$90^circ+frac{angle D}{2}$$ => $$ heta=90^circ+frac{130^circ}{2}$$ => $$ heta=90^circ+65^circ$$ => $$ heta=155^circ$$ => Ans - (C)
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