1. ABC is an isosceles triangle such that AB = AC = 30 cm and BC = 48 cm. AD is a median to base BC. What is the length (in cm) of AD?
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By: anil on 05 May 2019 02.26 am
Given : AB = AC = 30 cm and BC = 48 cm. AD is a median to base BC To find : AD = ? Solution : In an isosceles triangle, median is perpendicular to the base. => CD = $$frac{48}{2}=24$$ cm Thus, in right $$ riangle$$ ADC, => $$(AD)^2=(AC)^2-(CD)^2$$ => $$(AD)^2=(30)^2-(24)^2$$ => $$(AD)^2=900-576=324$$ => $$AD=sqrt{324}=18$$ cm => Ans - (A)
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