1. A cuboid of sides 5 cm, 10 cm and 20 cm are melted to form a new cube. What is the ratio between the total surface area of the cuboid and that of the cube?
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By: anil on 05 May 2019 02.26 am
Let edge of cube = $$a$$ cm Now, volume of cube = Volume of cuboid => $$a^3=5 imes10 imes20$$ => $$a=sqrt[3]{1000}=10$$ cm Ratio between the total surface area of the cuboid and that of the cube = $$frac{2(lb+bh+hl)}{6a^2}$$ = $$frac{2[(5 imes10)+(10 imes20)+(20 imes5)]}{6 imes(10)^2}$$ => $$frac{2 imes(50+200+100)}{600}=frac{700}{600}=frac{7}{6}$$ => Ans - (B)
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