1. An amount was lent for one year at the rate of 10% per annum compounding annually had the compounding been done half yearly, the interest would have increased by 80. What was the amount (in Rs) lent?
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By: anil on 05 May 2019 02.26 am
Let the amount rent = Rs. $$100x$$ Rate of interest = 10% and time period = 1 year Amount if compounded annually = $$P(1+frac{r}{100})^T$$ and if compounded half yearly = $$P(1+frac{r}{200})^{2T}$$ According to ques, required difference : => $$[100x(1+frac{10}{200})^2]-[100x(1+frac{10}{100})^1]=80$$ => $$[100x imes(frac{21}{20})^2]-[100x imes(frac{11}{10})]=80$$ => $$frac{441x}{4}-110x=80$$ => $$frac{441x-440x}{4}=80$$ => $$x=80 imes4=320$$ $$ herefore$$ Sum lent = $$100 imes320=Rs.$$ $$32,000$$ => Ans - (B)
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