1. If $$\frac{(1 + cosA)}{(1 - cosA)}$$ = x, then x is





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  • By: anil on 05 May 2019 03.28 am
    Expression : $$frac{(1 + cosA)}{(1 - cosA)}$$ = x Multiplying both numerator and denominator by $$(1-cosA)$$ = $$frac{1+cosA}{1-cosA} imes frac{(1-cosA)}{(1-cosA)}$$ = $$frac{1-cos^2A}{(1-cosA)^2} = frac{sin^2A}{(1-cosA)^2}$$ Dividing both numerator and denominator by $$(cos^2A)$$ = $$frac{sin^2A}{cos^2A}divfrac{(1-cosA)^2}{cos^2A}$$ = $$tan^2A div (frac{1-cosA}{cosA})^2$$ = $$frac{tan^2A}{(secA-1)^2}$$ => Ans - (D)
  • By: anil on 05 May 2019 03.28 am
    Expression : $$frac{(1 + cosA)}{(1 - cosA)}$$ = x Multiplying both numerator and denominator by $$(1-cosA)$$ = $$frac{1+cosA}{1-cosA} imes frac{(1-cosA)}{(1-cosA)}$$ = $$frac{1-cos^2A}{(1-cosA)^2} = frac{sin^2A}{(1-cosA)^2}$$ Dividing both numerator and denominator by $$(cos^2A)$$ = $$frac{sin^2A}{cos^2A}divfrac{(1-cosA)^2}{cos^2A}$$ = $$tan^2A div (frac{1-cosA}{cosA})^2$$ = $$frac{tan^2A}{(secA-1)^2}$$ => Ans - (D)
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