1. The length of the diagonal of a rectangle is 10 cm and that of one side is 8 cm. What is the area of this rectangle?
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By: anil on 05 May 2019 02.14 am
Let breadth of rectangle = $$b$$ cm and length, $$l = 8$$ cm Diagonal of rectangle = $$sqrt{l^2+b^2}=10$$ => $$(8)^2+(b)^2=(10)^2$$ => $$(b)^2 = 100-64=36$$ => $$b=sqrt{36}$$ cm $$ herefore$$ Area of rectangle = $$l imes b$$ = $$8 imes 6 = 48$$ $$cm^2$$ => Ans - (B)
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