1. Of the 3 numbers whose average is 77, the first is 3/4 times the sum of other 2. The first number is





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  • By: anil on 05 May 2019 02.14 am
    Let the three numbers be $$x,y,z$$ Average of three numbers = $$frac{x + y + z}{3} = 77$$ => $$x+y+z=77 imes 3 = 231$$ According to ques, => $$x = frac{3}{4} imes (y + z)$$ => $$x = frac{3}{4} imes (231 - x)$$ => $$4x = 693 - 3x$$ => $$4x + 3x = 7x = 693$$ => $$x = frac{693}{7} = 99$$ => Ans - (C)
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